1 . 1-x2d2ydx2-xdydx=2

• A. $y={\cos }^{-1}\left(x\right)$
• B. $y={\left({\cos }^{-1}\left(x\right)\right)}^2$
• C. $y=y={\sin }^{-1}\left(x\right)$
• D. $y={\tan }^{-1}\left(x\right)$

Answer: Option B

Explanation: