• A. $s{p}^3$
• B. $s{p}^2$
• C. $sp$
• D. $s{p}^{3}d$

Answer: Option B

Explanation:

• A. $2Na+C{l}_2\to 2NaCl$
• B. $AgN{O}_3+NaCl\to NaN{O}_3+AgCl$
• C. $C{l}_2+H_{2}O\to HCl+HOCl$
• D. $FeC{l}_3+SnC{l}_2\to SnC{l}_4+FeC{l}_2$

Answer: Option C

Explanation:

• A. $C{O}_2$
• B. $H_{2}S$
• C. $C_2{H}_2$
• D. $O_2$

Answer: Option B

Explanation:

• A. $HCOOH+HCOONa$
• B. $NaOH+NaCl$
• C. $Aq.N{H}_3+NaOH$
• D. $Aq.N{H}_3+N{H}_{4}Cl$

Answer: Option D

Explanation:

• A. $K_w=1\times {10}^{-14}$
• B. $P{K}_w=14$
• C. $\left[H_3{O}^4\right]\left[OH\right]=K_w$
• D. $K_w=1\times {10}^{-14}M$

Answer: Option D

Explanation:

• A. $B_{e}C{l}_2$
• B. $PC{l}_5$
• C. $BC{l}_3$
• D. $C{l}_2$

Answer: Option B

Explanation:

• A. $H^{+}\left(aq\right)/H_2\left(g\right),Pt$
• B. $C{u}^{2+}\left(aq\right)/Cu\left(s\right)$
• C. $N{a}^{+}\left(aq\right)/Na\left(s\right)$
• D. $Pt\left(s\right)/F\left(g\right)/F^{-}\left(aq\right)$

Answer: Option C

Explanation:

• A. $-CHO$
• B. $-N{O}_2$
• C. $-{\mathrm{NH}}_2$
• D. $-{\mathrm{SO}}_3\mathrm{H}$

Answer: Option C

Explanation:

• A. $3.34\times {10}^{22}$
• B. $6.023\times {10}^{23}$
• C. $2.989\times {10}^{23}$
• D. $18$

Answer: Option A

Explanation:

• A. $mold{m}^{-3}$
• B. $ppm$
• C. $kj mo{l}^{-1}$
• D. $molarity$

Answer: Option C

Explanation:

• A. $C{O}_2$
• B. $C$
• C. $C_x{H}_y$
• D. $CO$

Answer: Option C

Explanation:

• A. $NaCl$
• B. $NaOH$
• C. $N{a}_{2}C{O}_3$
• D. $NaN{O}_3$

Answer: Option C

Explanation:

• A. $\mathrm{NaOH}+\mathrm{HCl}$
• B. ${\mathrm{H}}^{+}+{\mathrm{OH}}^{-}$
• C. ${\mathrm{Na}}^{+}\left({\mathrm{H}}_2\mathrm{O}\right)+\mathrm{Cl}\left({\mathrm{H}}_2\mathrm{O}\right)$
• D. $\mathrm{NaOCl}+{\mathrm{H}}_2$

Answer: Option C

Explanation:

• A. ${\mathrm{molLs}}^{-1}$
• B. ${\mathrm{molL}}^{-1}{\mathrm{s}}^{-1}$
• C. ${\mathrm{molL}}^{-2}{\mathrm{s}}^{-1}$
• D. ${\mathrm{molL}}^{-1}\mathrm{s}$

Answer: Option B

Explanation:

• A. $\mathrm{HCHO}$
• B. ${\mathrm{CH}}_3-\mathrm{CHO}$
• C. $\mathrm{Ph}-\mathrm{CHO}$
• D. ${\mathrm{CH}}_3-\mathrm{CO}-{\mathrm{CH}}_3$

Answer: Option B

Explanation: