1141 . A sells an article which costs him Tk. 400 to B at a profit of 20%. B then sells it to C, making a profit of 10% on the price he paid to A. How much does C pay to B?

A. Tk. 472
B. Tk. 476
C. Tk. 528
D. Tk. 532

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Answer: Option C

Explanation:

At 20% profit A sold the article to B at (400+ 400*20/100)= 480 tk.

At 10% profit B then sold it to C at (480+ 480*10/100)=528 tk

so, C pays tk 528 to B.

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পূবালী ব্যাংক লিমিটেড || সিনিয়র অফিসার (30-09-2023) || 2023

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1142 . A set has exactly five consecutive positive integers starting with 1. What is the percentage decrease in the average of the numbers when the greatest one of the numbers is removed from the set?

A. 12.5
B. 8.5
C. 16.66
D. 15.2

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Answer: Option C

Explanation:

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Standard Bank Plc || Trainee Assistant Officer (15-03-2025) || 2025

A. 2%
B. 2.5%
C. 20%
D. 25%

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Answer: Option C

Explanation:

12.5 - 10/12.50

= 25/125 × 100%

= 20% (ans)

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1144 . A shirt marked Tk.12.50 is sold at Tk.10.00. The rate of discount on the marked price is--

A. 2%
B. 2.5%
C. 20%
D. 25%

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Answer: Option C

Explanation:

12.5 - 10/12.50

= 25/125 × 100%

= 20% (ans)

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1145 . A shirt was marked down 20% the first week and another 20% the next week. What percent of the regular price was the final cost of the shirt after two markdowns?

A. 30%
B. 36%
C. 40%
D. 64%
E. None of these

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Answer: Option B

Explanation:

±a±b+(ab)/100

=-20-20+(20×20)/100

=|-36%|

=36%

(ans)

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1146 . A Shopkeeper buys 100 mangoes at Tk. 12 each. He sell 60 mangoes at Tk. 17.40 each and x mangoes at Tk. 11.31 each. The Shopkeeper makes a profit of at least 10%. Find the least possible value of x.

A. 24
B. 25
C. 27
D. 28

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Answer: Option B

Explanation:

Let's calculate the cost price and selling price to determine the least possible value of x for the shopkeeper to make a profit of at least 10%.

Cost Price (CP) of 100 mangoes = Tk. 12 each Total Cost Price of 100 mangoes = 100 * Tk. 12 = Tk. 1200

Selling Price (SP) of 60 mangoes = Tk. 17.40 each Total Selling Price of 60 mangoes = 60 * Tk. 17.40 = Tk. 1044

Now, we need to find the SP of the remaining (100 - 60 = 40) mangoes to cover the cost price and achieve a profit of at least 10%.

Let x be the number of mangoes sold at Tk. 11.31 each.

Total SP of x mangoes = x * Tk. 11.31

To make a profit of at least 10%, the SP must be at least 110% of the CP.

So, 110% of CP = 1.1 * Tk. 1200 = Tk. 1320

Now, we can set up an equation for the remaining mangoes:

Total SP of x mangoes + Tk. 1044 (SP of the first 60 mangoes) = Tk. 1320

x * Tk. 11.31 + Tk. 1044 = Tk. 1320

Now, subtract Tk. 1044 from both sides:

x * Tk. 11.31 = Tk. 1320 - Tk. 1044

x * Tk. 11.31 = Tk. 276

Now, divide both sides by Tk. 11.31 to find the value of x:

x = Tk. 276 / Tk. 11.31

x ≈ 24.37

Since x must be a whole number (representing the number of mangoes), we can round up to the nearest whole number to ensure a profit of at least 10%.

Rounding up, x = 25

So, the least possible value of x is 25 to achieve a profit of at least 10%.

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1147 . A shopkeeper carns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is

A. 45:56
B. 45:51
C. 47:56
D. 47:51

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Answer: Option A

Explanation:

Let the CP of book = Tk.x
Then, SP of book = (100 + 12) × x/100 = 112x/100
Now. the printed price = Tk.y
Then, after the discount, the SP
= (100−10) × y/100 = 90y/100
Since both SP are same.
Then, 112x/100 = 90y/100 = xy = 45/56
= 45 : 56.

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সমন্বিত পাঁচ ব্যাংক || অফিসার ক্যাশ - 06.11.2021

A. 5 liters
B. 6 liters
C. 7 liters
D. 8 liters
E. None of these

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Answer: Option B

Explanation:

Hints:

x লিটার Q উপাদান আছে = x এর 10/100 = x/10

10 লিটার Q উপাদান আছে = 10এর 2/100 = 1/5

Z লিটারে Q উপাদান আছে = ( x + 10) এর 5/100 = (x + 10)/20

শর্তমতে, x/10 + 1/5 = (x + 10) / 20

10x + 20 = 5x + 50

10x - 5x = 50 - 20

5x = 30

x = 6

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1149 . A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Tk. 392, what was his profit ?

A. Tk. 18.20
B. Tk. 70
C. Tk. 72
D. Tk. 88.25

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Answer: Option C

Explanation:

ধরি, ক্রয়মূল্য x টাকা

x + x × 2.25/100 = 392

1.225x = 392

x = 392/1.225

= 392 ×1000 /1225

x = 320

লাভ = 392 - 320 = 72 টাকা

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1150 . A shopkeeper has sufficient money to buy 50 books. On reduction in the price of each book by Tk. 4, he could buy 10 books more. How much money does he has?

A. Tk. 1000
B. Tk. 1200
C. Tk. 1500
D. Tk. 2000

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Answer: Option B

Explanation:

Let, per price = x

50 × x = (x-4) × 60

বা, 50x = 60x - 240

বা, -10x = -240

সুতরাং , x = 24

Amount of money he has

= (50 × 24) = 1200 TK .

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বাংলাদেশ ব্যাংক || অফিসার (ক্যাশ) (21-07-2023)

A. 50 tk
B. 125 tk
C. 200 tk
D. 300 tk

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Answer: Option C

Explanation:

7.5 % ক্ষতিতে দ্রব্যটির বিক্রয়মূল্য

= 100 - 7.5 = 92.5 টাকা

10% কমে দ্রব্যটির ক্রয়মূল্য = 100 - 10 = 90 টাকা

আবার, 20% লাবে দ্রব্যটির বিক্রয়মূল্য

= 90 + 90 এর 20%

= 90 + ( 90 × 20)/100 = 108 টাকা

∴ বিক্রয়মূল্য বেশি হয় = 108 - 92.5 = 15.5 টাকা

অর্থাৎ বিক্রয়মূল্য 15.5 টাকা বেশি হয় ক্রয়মূল্য = 100 টাকা

∴বিক্রয়মূল্য 31 টাকা বেশি হয় ক্রয়মূল্য

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সমন্বিত ৬ ব্যাংক ও আর্থিক প্রতিষ্ঠান - সহকারী প্রোগ্রামার - 18.03.2021

A. 232
B. 260
C. 230
D. 330
E. None of them

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Answer: Option C

Explanation:

দেওয়া আছে, কর সহ তালিকামূল্য = 460 টাকা
30% ছাড় এর পর বিক্রয়মূল্য হবে = (460 - 30% এর 460) = 322 টাকা
প্রশ্নে বলা হয়েছে, ছাড় দেয়ার পরও দোকানদারের 40% লাভ হয় । অর্থাৎ 40% লাভে বিক্রয়মূল্য = (100 + 40) = 140
বিক্রয়মূল্য 140 টাকা হলে ক্রয়মূল্য 100 টাকা
বিক্রয়মূল্য 322 টাকা হলে ক্রয়মূল্য = 230

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1153 . A shopkeeper mixes two varieties of tea. One costing Tk.35 per kg and another at Tk.45 per kg in the ratio 3 : 2. If he sells the mixed variety at 41.60 per kg, his gain or loss percent is---

A. 4% gain
B. 4% loss
C. 20/3% gain
D. 20/3% loss

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Answer: Option C

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1154 . A shopkeeper purchase 15 mangoes for Tk. 10 and sells them at 10 mangoes for Tk. 15. Thus, he earns a profit of-

A. 50%
B. 75%
C. 80%
D. 125%

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Answer: Option D

Explanation:

Let's calculate the cost price (CP) and selling price (SP) for the mangoes:

Cost Price (CP) of 15 mangoes = Tk. 10 Cost Price (CP) of 1 mango = Tk. 10 / 15 = Tk. 2/3

Selling Price (SP) of 10 mangoes = Tk. 15 Selling Price (SP) of 1 mango = Tk. 15 / 10 = Tk. 3/2

Now, let's calculate the profit percentage:

Profit per mango = Selling Price (SP) per mango - Cost Price (CP) per mango Profit per mango = (Tk. 3/2) - (Tk. 2/3) Profit per mango = (3/2) - (2/3) Profit per mango = (9/6) - (4/6) Profit per mango = (5/6)

Now, calculate the profit percentage:

Profit Percentage = (Profit per mango / Cost Price per mango) * 100 Profit Percentage = [(5/6) / (2/3)] * 100 Profit Percentage = [(5/6) * (3/2)] * 100 Profit Percentage = (15/12) * 100 Profit Percentage = (5/4) * 100 Profit Percentage = 125%

So, the shopkeeper earns a profit of 125%.

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সমন্বিত ৫ ব্যাংক || অফিসার (ক্যাশ) (11-03-2022)

A. 10
B. 15
C. 20
D. 25

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Answer: Option C

Explanation:

Let the price of 4 mangoes bought be X.

Price per mango bought = X/4

Price per mango sold = X/5

Loss = (X/4 - X/5) / (X/4) × 100% = (X/20) / (X/4) ×100% = 20%

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1141 . A sells an article which costs him Tk. 400 to B at a profit of 20%. B then sells it to C, making a profit of 10% on the price he paid to A. How much does C pay to B?

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1142 . A set has exactly five consecutive positive integers starting with 1. What is the percentage decrease in the average of the numbers when the greatest one of the numbers is removed from the set?

1143 . A shirt marked TK. 12.50 is sold at TK. 10.00. The rate of discount on the marked price is -

1144 . A shirt marked Tk.12.50 is sold at Tk.10.00. The rate of discount on the marked price is--

1145 . A shirt was marked down 20% the first week and another 20% the next week. What percent of the regular price was the final cost of the shirt after two markdowns?

1146 . A Shopkeeper buys 100 mangoes at Tk. 12 each. He sell 60 mangoes at Tk. 17.40 each and x mangoes at Tk. 11.31 each. The Shopkeeper makes a profit of at least 10%. Find the least possible value of x.

1147 . A shopkeeper carns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is

1148 . A shopkeeper combined X liters of a solution containing 10% of certain material Q, with 10 liters of another solution that contained 2% of that materiale Q, to produce Z liters of a solution that had 5% of Q. What is the value of X?

1149 . A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Tk. 392, what was his profit ?

1150 . A shopkeeper has sufficient money to buy 50 books. On reduction in the price of each book by Tk. 4, he could buy 10 books more. How much money does he has?

1151 . A shopkeeper lost 7.5% by selling an article. If he had bought it at 10% less and sold it for taka 31 more he would have gained 20%. Find the cost price of the article.

1152 . A shopkeeper marks an article at such a price that after allowing a discount of 30% on the tag price he makes a profit of 40% . If the tag price of the article including tax is Tk. 460 . then the cost price of that article is--

1153 . A shopkeeper mixes two varieties of tea. One costing Tk.35 per kg and another at Tk.45 per kg in the ratio 3 : 2. If he sells the mixed variety at 41.60 per kg, his gain or loss percent is---

1154 . A shopkeeper purchase 15 mangoes for Tk. 10 and sells them at 10 mangoes for Tk. 15. Thus, he earns a profit of-

1155 . A shopkeeper sells 5 mangoes at a price he bought 4 mangoes. What is the percentage (%) of loss or gain?

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